Advertisements
Advertisements
प्रश्न
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
z2 – 16
Advertisements
उत्तर
z2 – 16 = z2 – 42
We have a2 – b2 = (a + b)(a – b)
let a = z and b = 4,
z2 – 42 = (z + 4)(z – 4)
APPEARS IN
संबंधित प्रश्न
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(4 – mn)(mn + 4)
Factorise: 4x2 – 9y2
The pathway of a square paddy field has 5 m width and length of its side is 40 m. Find the total area of its pathway. (Note: Use suitable identity)
The value of p for 512 – 492 = 100p is 2.
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Using suitable identities, evaluate the following.
9.8 × 10.2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
25ax2 – 25a
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 625y4
Verify the following:
(m + n)(m2 – mn + n2) = m3 + n3
Find the value of a, if pqa = (3p + q)2 – (3p – q)2
