Advertisements
Advertisements
प्रश्न
Factorise the following:
a2 + 10a – 600
Advertisements
उत्तर
Product = – 600, sum = 10
Split the middle term as 30a and – 20a
a2 + 10a – 600 = a2 + 30a – 20a – 600
= a(a + 30) – 20(a + 30)
= (a + 30)(a – 20)
APPEARS IN
संबंधित प्रश्न
f(x) = 4x4 − 3x3 − 2x2 + x − 7, g(x) = x − 1
If the polynomials ax3 + 3x2 − 13 and 2x3 − 5x + a, when divided by (x − 2) leave the same remainder, find the value of a.
The polynomials ax3 + 3x2 − 3 and 2x3 − 5x + a when divided by (x − 4) leave the remainders R1 and R2 respectively. Find the value of the following case, if R1 = R2.
f(x) = x3 −6x2 − 19x + 84, g(x) = x − 7
Find the value of a such that (x − 4) is a factors of 5x3 − 7x2 − ax − 28.
Find the values of a and b, if x2 − 4 is a factor of ax4 + 2x3 − 3x2 + bx − 4.
If x + a is a factor of x4 − a2x2 + 3x − 6a, then a =
If x + 2 and x − 1 are the factors of x3 + 10x2 + mx + n, then the values of m and n are respectively
Factorise the following:
y2 – 16y – 80
Factorise:
x3 – 6x2 + 11x – 6
