Advertisements
Advertisements
प्रश्न
Factorise the following:
a2 + 10a – 600
Advertisements
उत्तर
Product = – 600, sum = 10

Split the middle term as 30a and – 20a
a2 + 10a – 600 = a2 + 30a – 20a – 600
= a(a + 30) – 20(a + 30)
= (a + 30)(a – 20)
APPEARS IN
संबंधित प्रश्न
Identify polynomials in the following:
`q(x)=2x^2-3x+4/x+2`
Identify constant, linear, quadratic and cubic polynomials from the following polynomials:
`q(x)=4x+3`
f(x) = 2x4 − 6x3 + 2x2 − x + 2, g(x) = x + 2
f(x) = x3 − 6x2 + 11x − 6, g(x) = x2 − 3x + 2
If x3 + 6x2 + 4x + k is exactly divisible by x + 2, then k =
If x + 2 and x − 1 are the factors of x3 + 10x2 + mx + n, then the values of m and n are respectively
One factor of x4 + x2 − 20 is x2 + 5. The other factor is
Factorise the following:
a4 – 3a2 + 2
Factorise the following:
`1/x^2 + 1/y^2 + 2/(xy)`
(a + b – c)2 is equal to __________
