Advertisements
Advertisements
प्रश्न
f(x) = 4x3 − 12x2 + 14x − 3, g(x) 2x − 1
Advertisements
उत्तर
Let us denote the given polynomials as
`f(x) = 4x^2 - 12x^3 - 12x^2 + 14x - 3,`
`g(x) = 2x - 1`
`⇒ g (x) = 2 (x - 1/2)`
We have to find the remainder when f(x) is divided by g(x).
By the remainder theorem, when f(x) is divided by g(x) the remainder is
`f(1/2) = 4(1/2)^3 - 12(1/2)^2 + 14 (1/2) - 3`
` = 4 xx 1/8 - 12 xx 1/4 + 14 xx 1/2 - 3`
` = 1/2 -3 + 7 - 3`
`= 3/2`
Now we will calculate the remainder by actual division

So the remainder by actual division is `3/2` .
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`sqrt3x-7`
Identify polynomials in the following:
`g(x)=2x^3-3x^2+sqrtx-1`
Find the remainder when x3 + 3x2 + 3x + 1 is divided by \[x - \frac{1}{2}\].
x4 − 7x3 + 9x2 + 7x − 10
x4 + 10x3 + 35x2 + 50x + 24
When x3 − 2x2 + ax − b is divided by x2 − 2x − 3, the remainder is x − 6. The values of a and b are respectively
If x2 − 1 is a factor of ax4 + bx3 + cx2 + dx + e, then
Factorise the following:
a2 + 10a – 600
Factorise the following:
12x2 + 36x2y + 27y2x2
Which of the following has x – 1 as a factor?
