Advertisements
Advertisements
प्रश्न
Factorise the following:
`1/x^2 + 1/y^2 + 2/(xy)`
Advertisements
उत्तर
`1/x^2 + 1/y^2 + 2/(xy) = (1/x)^2 + (1/y)^2 + 2(1/x) xx 1/y`
= `(1/x + 1/y)^2` ...[a2 + b2 + 2ab = (a + b)2]
APPEARS IN
संबंधित प्रश्न
If x = 0 and x = −1 are the roots of the polynomial f(x) =2x3 − 3x2 + ax + b, find the value of a and b.
f(x) = 3x3 + x2 − 20x +12, g(x) = 3x − 2
Find the values of p and q so that x4 + px3 + 2x3 − 3x + q is divisible by (x2 − 1).
What must be added to x3 − 3x2 − 12x + 19 so that the result is exactly divisibly by x2 + x - 6 ?
If \[x = \frac{1}{2}\] is a zero of the polynomial f(x) = 8x3 + ax2 − 4x + 2, find the value of a.
If x − 3 is a factor of x2 − ax − 15, then a =
If x + a is a factor of x4 − a2x2 + 3x − 6a, then a =
Factorise the following:
p² – 6p – 16
Factorise the following:
12x2 + 36x2y + 27y2x2
Factorise the following:
m2 + 2mn – 24n2
