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प्रश्न
Express the given complex number in the form a + ib: i–39
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उत्तर
We get, `i^39 = 1/(i^39) = i/(i^2)^19 i`
= `1(-1)^19 i. = 1/(-i)` [∵ i2 = -1]
= `1/((-1).i) = 1/(-i)`
= `- 1/ixxi/i`
= `(-i)/i^2`
= `(-i)/(-1)`
= i
= 0 + 1i
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