Advertisements
Advertisements
प्रश्न
Express the following as a single logarithm:
`2 "log" 3 - (1)/(2) "log" 16 + "log" 12`
Advertisements
उत्तर
`2 "log" 3 - (1)/(2) "log" 16 + "log" 12`
= `2 "log" 3 - (1)/(2) "log" 2^4 + "log" (2^2 xx 3)`
= `2 "log" 3 - (1)/(2) xx 4 "log" 2 + "log" 2^2 + "log" 3`
= 2 log 3 - 2 log 2 + 2 log 2 + log 3
= 3 log 3
= log 33
= log 27.
APPEARS IN
संबंधित प्रश्न
Given 2 log10 x + 1 = log10 250, find :
(i) x
(ii) log10 2x
Given: log3 m = x and log3 n = y.
Express 32x - 3 in terms of m.
Express the following in terms of log 2 and log 3: log 54
Express the following in terms of log 2 and log 3: `"log"root(5)(216)`
Write the logarithmic equation for:
E = `(1)/(2)"m v"^2`
Simplify the following:
`2 "log" 5 +"log" 8 - (1)/(2) "log" 4`
Simplify the following:
`3"log" (32)/(27) + 5 "log"(125)/(24) - 3"log" (625)/(243) + "log" (2)/(75)`
If log1025 = x and log1027 = y; evaluate without using logarithmic tables, in terms of x and y: log103
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log45
If log 8 = 0.90, find the value of each of the following: `"log"sqrt(32)`
