If Log 2 = 0.3010, Log 3 = 0.4771 and Log 5 = 0.6990, Find the Values Of: Log18 - Mathematics

If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log18

बेरीज

log18
= log (2 x 3²)
= log 2 + log 3²
= log 2 + 2 log 3
= 0.3010 + (2 x 0.4771)
= 1.2552.

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Expansion of Expressions with the Help of Laws of Logarithm

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पाठ 10: Logarithms - Exercise 10.2

पाठ 10 Logarithms
Exercise 10.2 | Q 19.1

Given 3log x + `1/2`log y = 2, express y in term of x.

Prove that : (log a)² - (log b)² = log `(( a )/( b ))` . Log (ab)

If log 27 = 1.431, find the value of : log 9

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Prove that:

log₁₀ 125 = 3(1 - log₁₀2).

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Express the following as a single logarithm:

`2 + 1/2 "log" 9 - 2 "log" 5`

Express the following as a single logarithm:

`3"log"(5)/(8) + 2"log"(8)/(15) - (1)/(2)"log"(25)/(81) + 3`

If log 8 = 0.90, find the value of each of the following: `"log"sqrt(32)`

Find the value of:

`("log"sqrt125 - "log"sqrt(27) - "log"sqrt(8))/("log"6 - "log"5)`