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प्रश्न
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log18
बेरीज
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उत्तर
log18
= log (2 x 32)
= log 2 + log 32
= log 2 + 2 log 3
= 0.3010 + (2 x 0.4771)
= 1.2552.
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Expansion of Expressions with the Help of Laws of Logarithm
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