Advertisements
Advertisements
प्रश्न
Express the following as a single logarithm:
`(1)/(2)"log"25 - 2"log"3 + "log"36`
Advertisements
उत्तर
`(1)/(2)"log"25 - 2"log"3 + "log"36`
= `(1)/(2)"log"5^2 - 2"log"3 + "log"(2^2 xx 3^2)`
= `(1)/(2) xx 2"log"5 - 2"log"3 + "log"2^2 + "log3^2`
= log5 + 2log2
= log5 + log22
= log5 + log4
= log(5 x 4)
= log20.
APPEARS IN
संबंधित प्रश्न
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 1.2
Prove that : (log a)2 - (log b)2 = log `(( a )/( b ))` . Log (ab)
If log (a + 1) = log (4a - 3) - log 3; find a.
If log x = p + q and log y = p - q, find the value of log `(10x)/y^2` in terms of p and q.
If log1025 = x and log1027 = y; evaluate without using logarithmic tables, in terms of x and y: log103
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: `"log" sqrt(72)`
If 2 log y - log x - 3 = 0, express x in terms of y.
If log 8 = 0.90, find the value of each of the following: `"log"sqrt(32)`
Simplify: log b ÷ log b2
Find the value of:
`("log"sqrt125 - "log"sqrt(27) - "log"sqrt(8))/("log"6 - "log"5)`
