Advertisements
Advertisements
प्रश्न
Express the following as a single logarithm:
`(1)/(2)"log"25 - 2"log"3 + "log"36`
Advertisements
उत्तर
`(1)/(2)"log"25 - 2"log"3 + "log"36`
= `(1)/(2)"log"5^2 - 2"log"3 + "log"(2^2 xx 3^2)`
= `(1)/(2) xx 2"log"5 - 2"log"3 + "log"2^2 + "log3^2`
= log5 + 2log2
= log5 + log22
= log5 + log4
= log(5 x 4)
= log20.
APPEARS IN
संबंधित प्रश्न
Given 3log x + `1/2`log y = 2, express y in term of x.
Given: log3 m = x and log3 n = y.
Write down `3^(1 - 2y + 3x)` in terms of m and n.
Express the following in terms of log 2 and log 3: log 216
Express the following in terms of log 2 and log 3: `"log"(26)/(51) - "log"(91)/(119)`
Express the following as a single logarithm:
`"log"(81)/(8) - 2"log"(3)/(5) + 3"log"(2)/(5) + "log"(25)/(9)`
Express the following as a single logarithm:
`3"log"(5)/(8) + 2"log"(8)/(15) - (1)/(2)"log"(25)/(81) + 3`
Simplify the following:
`12"log" (3)/(2) + 7 "log" (125)/(27) - 5 "log" (25)/(36) - 7 "log" 25 + "log" (16)/(3)`
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 720
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: `"log"2(1)/(4)`
If log a = p and log b = q, express `"a"^3/"b"^2` in terms of p and q.
