Express the Following in Terms of Log 2 and Log 3: Log128

Express the following in terms of log 2 and log 3: log12⁸

योग

log12⁸
=log (3 x 2²)⁸
= 8log (3 x 2²)
= 8[log 3 + log2²]
= 8[log 3 + 2log 2].

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Expansion of Expressions with the Help of Laws of Logarithm

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अध्याय 7: Logarithms - Exercise 10.2

अध्याय 7 Logarithms
Exercise 10.2 | Q 1.6

If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 12

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