Advertisements
Advertisements
प्रश्न
Express the following in terms of log 2 and log 3: log128
योग
Advertisements
उत्तर
log128
=log (3 x 22)8
= 8log (3 x 22)
= 8[log 3 + log22]
= 8[log 3 + 2log 2].
shaalaa.com
Expansion of Expressions with the Help of Laws of Logarithm
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
