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प्रश्न
Explain De Broglie’s Hypothesis.
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उत्तर
- De Broglie proposed that a moving material particle of total energy E and momentum p has a wave associated with it (analogous to a photon).
- He suggested a relation between properties of the wave, like frequency and wavelength, with that of a particle, like energy and momentum.
p = `"E"/"c" = "hv"/"c" = "h"/lambda` - Thus, the frequency and wavelength of a wave associated with a material particle, of mass m moving with a velocity v, are given as
`"v" = "E"/"h"` and `lambda = "h"/"p" = "h"/"mv"` ….(1) - De Broglie referred to these waves associated with material particles as matter waves. The wavelength of the matter waves, given by equation (1), is now known as de Broglie wavelength and the equation is known as de Broglie relation.
संबंधित प्रश्न
What is the speed of a proton having de Broglie wavelength of 0.08 Å?
The de Broglie wavelengths associated with an electron and a proton are the same. What will be the ratio of
- their momenta
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Find the ratio of the de Broglie wavelengths of an electron and a proton when both are moving with the (a) same speed, (b) the same kinetic energy, and (c) the same momentum. State which of the two will have a longer wavelength in each case.
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The momentum of a photon of energy 1 MeV in kg m/s will be ______
The de Broglie wavelength associated with photon is, ____________.
If the radius of the innermost Bohr orbit is 0.53 Å, the radius of the 4th orbit is ______
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What is the momentum of a photon having frequency 1.5 x 1013 Hz?
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If the potential difference used to accelerate electrons is doubled, by what factor does the de-Broglie wavelength associated with the electrons change?
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(h = Plank's constant, m = mass of electron)
An electron is accelerated through a potential difference of 100 volts. Calculate de-Broglie wavelength in nm.
Calculate the de Broglie wavelength associated with an electron moving with a speed of `5 xx 10^6` m/s. `(m_e = 9.1 xx 10^(-31)kg)`
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