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प्रश्न
Explain the bonding in methane molecule using electron dot structure.
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उत्तर
Formation of methane molecule – Non-polar covalent compound:
| Atom | Electronic configuration | Nearest noble gas | To attain stable electronic the configuration of nearest noble gas |
| Carbon | `""_6^12"C"[2,4]` | Neon [2,8] | Carbon needs four electrons to complete the octet |
| Hydrogen | `""_1^1"H"[1]` | Helium [2] | Hydrogen needs one electron to complete the duplet |
One atom of carbon shares four electron pairs, one with each of the four atoms of hydrogen.
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| Before combination (4 [H] and 1 [C] atom) |
After combination (CH4 – Methane molecule) |
संबंधित प्रश्न
Name the element whose one of the allotropic forms is buckminsterfullerene.
Fill in the following blank with suitable word:
The form of carbon which is known as black lead is ...........
Which of the following cannot exhibit isomerism?
(a) C4H10
(b) C5H12
(c) C3H8
(d) C6H14
Explain the following briefly.
Pure water does not conduct electricity, but on adding sodium chloride to it, it starts conducting electricity.
Give examples for the following:
Two gaseous non polar compounds.
Draw an electron dot diagram to show the formation of the following compound.
Magnesium chloride [ H=1, C=6, Mg=12, Cl=17].
Define a covalent bond.
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
| \[\begin{array}{cc}\phantom{......}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\ \phantom{.....}|\phantom{....}|\phantom{....}|\\ \ce{H - C - C = C}\\\phantom{.....}|\phantom{.........}|\\ \phantom{.....}\ce{H}\phantom{........}\ce{H}\end{array}\] |
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
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Considering MgCl2 as ionic compound and CH4 as covalent compound give any two differences between these two compounds.


