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प्रश्न
Evaluate: `int_(pi/6)^(pi/3) cosx "d"x`
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उत्तर
`int_(pi/6)^(pi/3) cosx "d"x = [sin x]_(pi/6)^(pi/3)`
= `sin pi/3 - sin pi/6`
= `sqrt(3)/2 - 1/2`
= `(sqrt(3) - 1)/2`
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