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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Evaluate: ∫0π4sec4x dx

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प्रश्न

Evaluate: `int_0^(pi/4) sec^4x  "d"x`

बेरीज
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उत्तर

Let I = `int_0^(pi/4) sec^4x  "d"x`

= `int_0^(pi/4) sec^2x*sec^2 x  "d"x`

= `int_0^(pi/4) (1 + tan^2x)sec^2 x  "d"x`

Put tan x = t

∴ sec2x  dx = dt

When x = 0, t = 0 and when x = `pi/4`, t = 1

∴ I = `int_0^1(1 + "t"^2)"dt"`

= `int_0^1 "dt" + int_0^1 "t"^2  "dt"`

= `["t"]_0^1 + ["t"^3/3]_0^1`

= `(1 - 0) + 1/3(1^3 - 0)`

= `4/3`

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Methods of Evaluation and Properties of Definite Integral
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पाठ 2.4: Definite Integration - Short Answers II

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