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प्रश्न
Enlist the conclusions drawn by Rutherford from his α-ray scattering experiment.
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उत्तर
Rutherford concluded from a-particle scattering experiment that
- Most of the space in the atom is empty because most of the α-particles passed through the gold foil without getting deflected.
- A small fraction of a-particles were deflected indicating that the positive charge of the atom occupies very little space. A very small fraction of α- particles were deflected by 180°, indicating that all the positive charge and mass of the atom were concentrated in a very small volume within the atom.
From the data, Rutherford also concluded that the radius of the nucleus is about 105 times less than Mg2+ the radius of the atom
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संबंधित प्रश्न
Rutherford’s alpha-particle scattering experiment was responsible for the discovery of ______.
(a) What is the nucleus of an atom and what is the nature of charge on it?
(b) Name the scientist who discovered the nucleus of atom.
Name the particles used by Rutherford in his experiment on the discovery of nucleus. Also state the charge on these particles.
What conclusions were made from the observations of Gold foil experiment?
Which of the following statements about Rutherford’s model of atom are correct?
(i) considered the nucleus as positively charged
(ii) established that the α–particles are four times as heavy as a hydrogen atom
(iii) can be compared to solar system
(iv) was in agreement with Thomson’s model
Why did Rutherford select a gold foil in his α–ray scattering experiment?
Proton was discovered by ______.
In Rutherford’s experiment, the bouncing of alpha particles suggests that the nucleus of an atom is negatively charged.
To study the internal structure of the atom, Rutherford used ______.
The Rutherford α-particle experiment shows that most of the α-particles pass through almost unscattered. While some are scattered through large angles. What information does it give about the structure of the atom?
