Question

Each of the resistors shown in the figure has a resistance of 10 Ω and each of the batteries has an emf of 10 V. Find the currents flowing through the resistors a and bin the two circuits.

Answer 1

(a)

From the figure,

Potential difference between the two ends of resistor a = 10 V

Resistance of resistor a =10 Ω

∴ Current through a = \[\frac{10}{10} = 1 A\]

Since the two batteries are connected opposite each other,

potential difference between the terminals of b = 10 – 10 = 0 V

∴ Current through b = 0 A

 

(b)

From the figure,

Potential difference between the two ends of resistor a = 10 V.

Resistance of resistor a =10 Ω

∴ Current through a = \[\frac{10}{10} = 1 A\]

Since the two batteries are again connected opposite to each other,

Potential difference between terminal of b = 10 – 10 = 0 V

∴ Current through b = 0 A