मराठी

During a medical checkup, the number of heartbeats per minute of 40 patients were recorded and summarised as follows: Number of heartbeats per minute 64 – 68 68 – 72 72 – 76 76 – 80 80 – 84 84 – 88

Advertisements
Advertisements

प्रश्न

During a medical checkup, the number of heartbeats per minute of 40 patients were recorded and summarised as follows:

Number of heartbeats
per minute
64 – 68 68 – 72 72 – 76 76 – 80 80 – 84 84 – 88
Number of patients 6 8 10 12 3 1

Find the mean heartbeats per minute for these patients.

बेरीज
Advertisements

उत्तर

The class mark (xi) is calculated using the formula:

Class Mark (xi) = `("Lower Limit" + "Upper Limit")/2`

Number of Heartbeats
per Minute
(Class Interval)
Number of Patients
(fi)
Class Mark
(xi)
Product
(fixi)
64 – 68 6 66 6 × 66 = 396
68 – 72 8 70 8 × 70 = 560
72 – 76 10 74 10 × 74 = 740
76 – 80 12 78 12 × 78 = 936
80 – 84 3 82 3 × 82 = 246
84 – 88 1 86 1 × 86 = 86
Total Σfi = 40   Σfixi = 2964

Using the formula for the mean of grouped data:

Mean `(barx) = (sumf_ix_i)/(sumf_i)`

Substitute the values from the table:

`barx = 2964/40 = 74.1`

The mean heartbeats per minute for these patients is 74.1 bpm.
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive - EXERCISE 18A [पृष्ठ ८६०]

APPEARS IN

आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 18 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
EXERCISE 18A | Q 7. | पृष्ठ ८६०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×