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प्रश्न
During a medical checkup, the number of heartbeats per minute of 40 patients were recorded and summarised as follows:
| Number of heartbeats per minute |
64 – 68 | 68 – 72 | 72 – 76 | 76 – 80 | 80 – 84 | 84 – 88 |
| Number of patients | 6 | 8 | 10 | 12 | 3 | 1 |
Find the mean heartbeats per minute for these patients.
योग
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उत्तर
The class mark (xi) is calculated using the formula:
Class Mark (xi) = `("Lower Limit" + "Upper Limit")/2`
| Number of Heartbeats per Minute (Class Interval) |
Number of Patients (fi) |
Class Mark (xi) |
Product (fixi) |
| 64 – 68 | 6 | 66 | 6 × 66 = 396 |
| 68 – 72 | 8 | 70 | 8 × 70 = 560 |
| 72 – 76 | 10 | 74 | 10 × 74 = 740 |
| 76 – 80 | 12 | 78 | 12 × 78 = 936 |
| 80 – 84 | 3 | 82 | 3 × 82 = 246 |
| 84 – 88 | 1 | 86 | 1 × 86 = 86 |
| Total | Σfi = 40 | Σfixi = 2964 |
Using the formula for the mean of grouped data:
Mean `(barx) = (sumf_ix_i)/(sumf_i)`
Substitute the values from the table:
`barx = 2964/40 = 74.1`
The mean heartbeats per minute for these patients is 74.1 bpm.
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