Advertisements
Advertisements
प्रश्न
Draw circle with diameter: 8.4 cm
In above case, measure the length of the radius of the circle drawn.
Advertisements
उत्तर
AB is the diameter of circle
i.e. AB = 8.4 cm
and OA is the radius of a circle
`= 1/2 "of diameter" = 8.4/2 = 4.2` cm
i.e., OA = OB = 4.2 cm.
APPEARS IN
संबंधित प्रश्न
In fig. XP and XQ are tangents from X to the circle with centre O. R is a point on the circle. Prove that, XA + AR = XB + BR.
In figure, PA and PB are tangents from an external point P to the circle with centre O. LN touches the circle at M. Prove that PL + LM = PN + MN.
O is the centre of a circle of radius 10 cm. P is any point in the circle such that OP = 6 cm. A is the point travelling along the circumference. x is the distance from A to P. what are the least and the greatest values of x in cm? what is the position of the points O, P and A at these values?
Two concentric circles are of radii 6.5 cm and 2.5 cm. Find the length of the chord of the larger circle which touches the smaller circle.
In the given figure, PA and PB are two tangents to the circle with centre O. If ∠APB = 50° then what is the measure of ∠OAB.
In the given figure, two tangents AB and AC are drawn to a circle with centre O such that ∠BAC = 120°. Prove that OA = 2AB.
AB is a chord of a circle with centre O , AOC is a diameter and AT is the tangent at A as shown in Fig . 10.70. Prove that \[\angle\]BAT = \[\angle\] ACB.
In the following figure, tangents PQ and PR are drawn to a circle such that ∠RPQ = 30°. A chord RS is drawn parallel to the tangent PQ, then ∠RQS.
The length of tangent from an external point on a circle is always greater than the radius of the circle.
In the following figure, ∠OAB = 30º and ∠OCB = 57º. Find ∠BOC and ∠AOC.
