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प्रश्न
Divide and write the quotient and the remainder.
(3x + 2x2 + 4x3) ÷ (x − 4)
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उत्तर १
(3x + 2x2 + 4x3) ÷ (x − 4)
4x2 + 18x + 75
`x - 4")"overline( 4x^3 + 2x^2+3x+0)`
4x3 − 16x2
− −
18x2 + 3x + 0
18x2 − 72x
− +
75 + 0
75x − 300
− +
300
So, quotient = 4x2 + 18x + 75 and remainder = 300.
उत्तर २
3x + 2x2 + 4x3
Descending order
4x3 + 2x2 + 3x
x − 4
Polynomial Division
`(4x^3+2x^2+3x)/(x-4)`
(i) `(4x^3)/x = 4x^2`
4x2 (x − 4) = 4x2x − 16x2 = 4x3 − 16x2
(4x3 + 2x2) − (4x3 − 16x2) = 18x2
Bring down +3x:
18x2 + 3x
(ii) `(18x^2)/x = 18x`
18x (x − 4) = 18x2 − 72x
(18x2 + 3x) − (18x2 − 72x) = 75x
(iii) `(75x)/x = 75`
75(x − 4) = 75x − 300
75x − (75x − 300)
= 300
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