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प्रश्न
Divide: 81(p4q2r3 + 2p3q3r2 – 5p2q2r2) by (3pqr)2
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उत्तर
`(81("p"^4"q"^2"r"^3 + 2"p"^3"q"^3"r"^2 - 5"p"^2"q"^2"r"^2))/((3"pqr")^2)`
= `(81("p"^2"q"^2"r"^2)("p"^2"r" + 2"pq" - 5))/(9("p"^2"q"^2"r"^2))`
= `81/9 ("p"^2"q"^2"r"^2)^(1-1) ("p"^2"r" + 2"pq" - 5)`
= 9(p2r + 2pq – 5)
= 9p2r + 18pq – 45
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