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प्रश्न
Divide:
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उत्तर
\[ - 4 \div \frac{- 3}{5} = - 4 \times \frac{5}{- 3} = \frac{20}{3}\]
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संबंधित प्रश्न
Add the following rational numbers.
Re-arrange suitably and find the sum in each of the following:
What number should be added to \[\frac{- 5}{7}\] to get\[\frac{- 2}{3}?\]
What number should be subtracted from \[\frac{3}{7}\] to get\[\frac{5}{4}?\]
Multiply:
Find two rational numbers between \[\frac{- 2}{9} \text{and} \frac{5}{9} .\]
The population of India in 2004 - 05 is a rational number.
0 is the smallest rational number.
The average life expectancies of males for several states are shown in the table. Express each decimal in the form `p/q` and arrange the states from the least to the greatest male life expectancy. State-wise data are included below; more indicators can be found in the “FACTFILE” section on the homepage for each state.
| State | Male | `bb(p/q)` form | Lowest terms |
| Andhra Pradesh | 61.6 | ||
| Assam | 57.1 | ||
| Bihar | 60.7 | ||
| Gujarat | 61.9 | ||
| Haryana | 64.1 | ||
| Himachal Pradesh | 65.1 | ||
| Karnataka | 62.4 | ||
| Kerala | 70.6 | ||
| Madhya Pradesh | 56.5 | ||
| Maharashtra | 64.5 | ||
| Orissa | 57.6 | ||
| Punjab | 66.9 | ||
| Rajasthan | 59.8 | ||
| Tamil Nadu | 63.7 | ||
| Uttar Pradesh | 58.9 | ||
| West Bengal | 62.8 | ||
| India | 60.8 |
Source: Registrar General of India (2003) SRS Based Abridged Lefe Tables. SRS Analytical Studies, Report No. 3 of 2003, New Delhi: Registrar General of India. The data are for the 1995-99 period; states subsequently divided are therefore included in their pre-partition states (Chhatisgarh in MP, Uttaranchal in UP and Jharkhand in Bihar)
Show that x is rational, if x2 = 0.0004.
