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Differentiate Cos − 1 ( 4 X 3 − 3 X ) with Respect to Tan − 1 ( √ 1 − X 2 X ) , I F 1 2 < X < 1 ? - Mathematics

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प्रश्न

Differentiate \[\cos^{- 1} \left( 4 x^3 - 3x \right)\] with respect to \[\tan^{- 1} \left( \frac{\sqrt{1 - x^2}}{x} \right), \text{ if }\frac{1}{2} < x < 1\] ? 

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उत्तर

\[\text { Let, u } = \cos^{- 1} \left( 4 x^3 - 3x \right)\]

\[\text { Put, x } = \cos\theta\]

\[ \Rightarrow \theta = \cos^{- 1} x\]

\[\text { Now, u }= \cos^{- 1} \left( 4 \cos^3 \theta - 3\cos\theta \right)\]

\[ \Rightarrow u = \cos^{- 1} \left( \cos3\theta \right) . . . \left( i \right)\]

\[\text {  Let, v } = \tan^{- 1} \left( \frac{\sqrt{1 - x^2}}{x} \right)\]

\[ \Rightarrow v = \tan^{- 1} \left( \frac{\sqrt{1 - \cos^2 \theta}}{\cos\theta} \right) \]

\[ \Rightarrow v = \tan^{- 1} \left( \frac{\sin\theta}{\cos\theta} \right)\]

\[ \Rightarrow v = \tan^{- 1} \left( \tan\theta \right) . . . \left( ii \right)\]

\[\text { Here }, \]

\[ \frac{1}{2} < x < 1\]

\[ \Rightarrow \frac{1}{2} < \cos\theta < 1\]

\[ \Rightarrow 0 < \theta < \frac{\pi}{3}\]

\[\text { So, from equation } \left( i \right), \]

\[u = 3\theta .........\left[ \text { Since }, \cos^{- 1} \left( \cos\theta \right) = \theta, \text{ if }\theta \in \left[ 0, \pi \right] \right]\]

\[ \Rightarrow u = 3 \cos^{- 1} x\]

Differentiating it with respect to x,

\[\frac{du}{dx} = \frac{- 3}{\sqrt{1 - x^2}} . . . \left( iii \right)\]

\[\text{ From equation } \left( ii \right), \]

\[v = \theta ..........\left[ \text { Since }, \tan^{- 1} \left( \tan\theta \right) = \theta, \text{ if }\theta \in \left( - \frac{\pi}{2}, \frac{\pi}{2} \right) \right]\]

\[ \Rightarrow v = \cos^{- 1} x\]

Differentiating it with respect to x,

\[\frac{dv}{dx} = \frac{- 1}{\sqrt{1 - x^2}} . . . \left( iv \right)\]

\[\text { Dividing equation} \left( iii \right) \text { by } \left( iv \right), \]

\[\frac{\frac{du}{dx}}{\frac{dv}{dx}} = \left( \frac{- 3}{\sqrt{1 - x^2}} \right)\left( - \frac{\sqrt{1 - x^2}}{1} \right)\]

\[ \therefore \frac{du}{dv} = 3\]

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पाठ 11: Differentiation - Exercise 11.08 [पृष्ठ ११३]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 11 Differentiation
Exercise 11.08 | Q 16 | पृष्ठ ११३

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