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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Determine the minimum value of the function. f(x) = 2x3 – 21x2 + 36x – 20

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प्रश्न

Determine the minimum value of the function.

f(x) = 2x3 – 21x2 + 36x – 20

बेरीज
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उत्तर

f(x) = 2x3 – 21x2 + 36x – 20

∴ f'(x) = 6x2 – 42x + 36  and f''(x) = 12x – 42

Consider f '(x) = 0

∴ 6x2 – 42x + 36 = 0

∴ x2 – 7x + 6 = 0

∴ (x – 6)(x – 1) = 0

∴ x – 1 = 0 or x – 6 = 0

∴x = 6 or x = 1   

For x = 6,

f''(6) = 12(6) – 42

= 72 – 42

= 30 > 0

∴ f(x) minimum value at x = 6.

f''(1) = 12 – 42

= –30 < 0

∴ f(x) maximum value at x = 1.

f''(6) = 2(6)3 – 21(6)2 + 36(6) – 20

= 432 – 756 + 216 – 20

= –128

∴ The function f(x) has a minimum value of –128 at x = 6.

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