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प्रश्न
Describe the locus of points at distances less than or equal to 2.5 cm from a given point.
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उत्तर
The locus is the space inside and circumference of the circle with a radius of 2.5 cm and the centre is the given fixed point.
संबंधित प्रश्न
Construct a right angled triangle PQR, in which ∠Q = 90°, hypotenuse PR = 8 cm and QR = 4.5 cm. Draw bisector of angle PQR and let it meets PR at point T. Prove that T is equidistant from PQ and QR.
In triangle LMN, bisectors of interior angles at L and N intersect each other at point A. Prove that:
- Point A is equidistant from all the three sides of the triangle.
- AM bisects angle LMN.
In the figure given below, find a point P on CD equidistant from points A and B.
Construct a triangle ABC, with AB = 7 cm, BC = 8 cm and ∠ABC = 60°. Locate by construction the point P such that:
- P is equidistant from B and C.
- P is equidistant from AB and BC.
- Measure and record the length of PB.
Describe the locus of the centre of a wheel of a bicycle going straight along a level road.
Describe the locus of points at distances less than 3 cm from a given point.
Describe the locus of points at distances greater than or equal to 35 mm from a given point.
In the given figure, obtain all the points equidistant from lines m and n; and 2.5 cm from O.
Draw a triangle ABC in which AB = 6 cm, BC = 4.5 cm and AC = 5 cm. Draw and label:
- the locus of the centres of all circles which touch AB and AC,
- the locus of the centres of all the circles of radius 2 cm which touch AB.
Hence, construct the circle of radius 2 cm which touches AB and AC .
In a quadrilateral ABCD, if the perpendicular bisectors of AB and AD meet at P, then prove that BP = DP.
