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∫ D X √ 2 a X − X 2 = a N Sin − 1 [ X a − 1 ] the Value of N is You May Use Dimensional Analysis to Solve the Problem. - Physics

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प्रश्न

\[\int\frac{dx}{\sqrt{2ax - x^2}} = a^n \sin^{- 1} \left[ \frac{x}{a} - 1 \right]\] 
The value of n is

पर्याय

  • 0

  • -1

  • 1

  • none of these.

MCQ
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उत्तर

0
[ax] = [x2]
⇒ [a] = [x]    ...(1)
Dimension of LHS = Dimension of RHS

\[\Rightarrow \left[ \frac{dx}{\sqrt{x^2}} \right] = \left[ a^n \right]\]

\[ \Rightarrow \left[ \frac{L}{L} \right] = \left[ a^n \right] . . . (2) \]

\[[ L^0 ] = [ a^n ]\]

\[n = 0\]

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Notes

You may use dimensional analysis to solve the problem.

  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Introduction to Physics - MCQ [पृष्ठ ९]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 1 Introduction to Physics
MCQ | Q 6 | पृष्ठ ९

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