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प्रश्न
cosec4 θ − cosec2 θ = cot4 θ + cot2 θ
Prove the following:
cosec4 θ − cosec2 θ = cot2 θ + cot4 θ
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उत्तर १
LHS = cosec4 θ − cosec2 θ
LHS = cosec2 θ (cosec2 θ − 1)
LHS = (cot2 θ + 1)cot2 θ ...`{(cot^2 θ + 1 = cosec^2 θ),(∵ cot^2 θ = cosec^2 θ - 1):}`
LHS = cot4 θ + cot2 θ
RHS = cot4 θ + cot2 θ
RHS = LHS
Hence proved.
उत्तर २
RHS = cot4 θ + cot2 θ
RHS = cot2 θ (cot2 θ + 1)
RHS = (cosec2 θ − 1)cosec2 θ ...`{(cot^2 θ + 1=cosec^2 θ),(∵ cot^2θ = cosec^2 θ - 1):}`
RHS = cosec4 θ − cosec2 θ
LHS = cosec4 θ − cosec2 θ
RHS = LHS
Hence proved.
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Solution :
L.H.S. = cotθ + tanθ
= `cosθ/sinθ + sinθ/cosθ`
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= `1/sinθ xx 1/square`
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∴ cotθ + tanθ = cosecθ × secθ
