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प्रश्न
Construct an isosceles ∆ PQR such that PQ = PR = 6.5 cm and ∠PQR = 75°. Using a ruler and compasses only constructs a circumcircle to this triangle.
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उत्तर
Steps of Construction :
(i) Draw a line segment PQ = 6.5 cm
(ii) At Q, draw a ray making an angle of 75°.
(iii) Through P, with a radius of 6.5 cm, draw an arc which intersects the angle ray at R.
(iv) Join PR,
Δ PQR is the required triangle.
(v) Draw the perpendicular bisectors of sides PQ and PR intersecting each other at O.
(vi) Join OP, OQ and OR.
(vii) With centre O and radius equal to OP or OQ or OR draw a circle which passes through P, Q and R. This is the required circumcircle of Δ PQR
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संबंधित प्रश्न
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Construct a ∆ PQR such that:
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Construct an isosceles ∆ ABC such that:
AB = AC = 6.5 cm and ∠A = 60°
Construct an isosceles ∆ ABC such that:
BC = AB = 5.8 cm and ZB = 30°. Measure ∠A and ∠C.
Construct an equilateral Δ ABC such that:
Each side is 6 cm.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
Construct a ∆ ABC such that AB = 6 cm, BC = 5.6 cm and CA = 6.5 cm. Inscribe a circle to this triangle and measure its radius.
Construct an equilateral ∆ DEF whose one side is 5.5 cm. Construct an incircle to this triangle.
