Advertisements
Advertisements
प्रश्न
Construct an isosceles Δ ABC such that:
Base AB = 6.2 cm and base angle = 45°. Measure the other two sides of the triangle.
Advertisements
उत्तर
Steps of Construction:
We know that in an isosceles triangle, base angles are equal.
(i) Draw a line segment AB = 6.2 cm
(ii) At A and B, draw rays making an angle of 45° each which intersects each other at C.
∆ABC is the required triangle.
On measuring the equal sides, each is 4.3 cm (approx.) in length.
APPEARS IN
संबंधित प्रश्न
Construct a ∆ABC such that:
CB = 6.5 cm, CA = 4.2 cm and BA = 51 cm
Construct a ∆ABC such that:
BC = 4 cm, AC = 5 cm and AB = 3.5 cm
Construct a ∆ ABC such that:
BC = 6 cm, AC = 5.7 cm and ∠ACB = 75°
Construct a ∆ ABC such that:
AB = 6.5 cm, AC = 5.8 cm and ∠A = 45°
Construct a ∆ PQR such that:
PR = 5.8 cm, ∠P = 60° and ∠R = 45°. Measure ∠Q and verify it by calculations
Construct an isosceles Δ ABC such that:
Base AC = 5 cm and base angle = 75°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
