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प्रश्न
Construct a ΔABC in which AB + AC = 5.6 cm, BC = 4.5 cm, AB − AC = 1.5 cm and ∠B = 45°.
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उत्तर
Steps of construction:
Step 1: Draw a line segment BC of 4.5cm
Step 2: At B, draw an angle XBC of 45°
Step 3: With center B and radius 5 6 , cm draw an arc which intersects BX at D.
Step 4: Join DC
Step 5: Draw the perpendicular bisector of DC which intersects BD at A.
Step 6: Join AC
∴ΔABC is a required triangle
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