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प्रश्न
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
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उत्तर
Using the angle sum property, we can find the third angle of the triangle FEG.
∠F + ∠E + ∠G = 180°
⇒ 65° + ∠E + 45° = 180°
⇒ ∠E = 70°
Steps of construction:
- Draw a line EG = 6 cm.
- With E as a centre, draw ∠XEG = 70°.
- With G as a centre, draw ∠YGE = 45º.
- Let YG and XE meet at point F.
∆FEG is the required triangle.
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