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प्रश्न
Consider the figure and answer the following question.
If cell ‘A’ has ECell = 0.5V and cell ‘B’ has ECell = 1.1V then what will be the reactions at anode and cathode?
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उत्तर
Now cell ‘B’ acts as galvanic cell as it has higher emf and will push electrons into cell ‘A’.
The electrode reaction will be:
At anode: \[\ce{Zn -> Zn^{2+} + 2e^{-}}\]
At cathode: \[\ce{Cu^{2+} + 2e^{-} -> Cu}\]
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