Question

Consider the figure and answer the following question.

If cell ‘A’ has E_Cell = 0.5V and cell ‘B’ has E_Cell = 1.1V then what will be the reactions at anode and cathode?

Answer 1

Now cell ‘B’ acts as galvanic cell as it has higher emf and will push electrons into cell ‘A’.

The electrode reaction will be:

At anode: \[\ce{Zn -> Zn^{2+} + 2e^{-}}\]

At cathode: \[\ce{Cu^{2+} + 2e^{-} -> Cu}\]