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प्रश्न
| Class mark | 12.5 | 17.5 | 22.5 | 27.5 | 32.5 | 37.5 | 42.5 |
| Frequency | 12 | 17 | 22 | 27 | 30 | 21 | 16 |
- From the distribution, given above, construct a frequency table.
- Use the table obtained in part (a) to draw : (i) a histogram, (ii) an ogive.
तक्ता
आलेख
बेरीज
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उत्तर
(a) Difference in consecutive class marks = 17.5 − 12.5 = 5
First class interval will be 10 – 15 and so on.
| Class Mark | Class Interval | Frequency | c.f. |
| 12.5 | 10 – 15 | 12 | 12 |
| 17.5 | 15 – 20 | 17 | 29 |
| 22.5 | 20 – 25 | 22 | 51 |
| 27.5 | 25 – 30 | 27 | 78 |
| 32.5 | 30 – 35 | 30 | 108 |
| 37.5 | 35 – 40 | 21 | 129 |
| 42.5 | 40 – 45 | 16 | 145 |
Total = 145
(b) Now plot the points (15, 12), (20, 29), (25, 51), (30, 78), (35, 108), (40, 129), (45, 145) and join them to obtain an ogive.
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