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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Choose the correct alternative: Area of the circle centre at (1, 2) and passing through (4, 6) is

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प्रश्न

Choose the correct alternative:

Area of the circle centre at (1, 2) and passing through (4, 6) is

पर्याय

  • 10π

  • 25π

  • 100π

MCQ
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उत्तर

25π

Explanation:

r = CA

`= sqrt((4- 1)^2 + (6 - 2)^2)`

`= sqrt(9 + 16)`

`= sqrt 25`

= 5

∴ area = πr2

= π × 52

= 25 π

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पाठ 6: Circle - Miscellaneous Exercise 6 [पृष्ठ १३७]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 6 Circle
Miscellaneous Exercise 6 | Q I. (6) | पृष्ठ १३७

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