मराठी

Choose the Current Answer from the Options Given Below : Which of the Following Gas Dissolves in H2so4 To Give Alum? - Chemistry

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प्रश्न

Choose the current answer from the options given below :
Which of the following gas dissolves in H2SO4 to give alum?

पर्याय

  • SO2

  • H2S

  • S2O

  • SO3

MCQ
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उत्तर

SOgas dissolves in H2SO4 to give alum.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Study of Sulphur Compound: Sulphuric Acid - Exercise 3 [पृष्ठ २५१]

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फ्रँक Chemistry Part 2 [English] Class 10 ICSE
पाठ 10 Study of Sulphur Compound: Sulphuric Acid
Exercise 3 | Q 1.3 | पृष्ठ २५१

संबंधित प्रश्‍न

Comment, sulphuric acid is referred to as oil of vitriol.


Give reason for the following:
Red brown vapours are produced when concentrated sulphuric acid is added to hydrogen bromide.


Name the following:
Products obtained by dissolving sulphur dioxide and chlorine in water.


How are the following conversion brought about? Give equation and condition:
Aqueous barium chloride to barium sulphate.


Fill in the blank with appropriate word/words :
Oil of Vitriol is ___________


Some properties of sulphuric acid are listed below. Choose the property A, B, C or D which is responsible for the reaction (a) to (e). Some properties may be repeated.
A. Acid
B. Dehydrating agent
C. Non-volatile acid
D. Oxidizing agent

(a) \[\ce{C12H22O11 + nH2SO4 -> 12C + 11H2O + nH2SO4}\]
(b) \[\ce{S + 2H2SO4 -> 3SO2 + 2H2O}\]
(c) \[\ce{NaCl + 2H2SO4 -> NaHSO4 + HCl}\]
(d) \[\ce{CuO + 2H2SO4 -> CuSO4 + H2O}\] 
(e) \[\ce{Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2}\]


HCl, HNO3 and H2SO4 are formulae of three compounds. Which of these compounds has the highest boiling point and which has the lowest?


What property of conc. H2SO4 is made use of in the following case? Give an equation for the reaction in this case:

It’s reaction with ethanol.


Which property of sulphuric acid accounts for its use as a dehydrating agent?


The following is the typical property of dilute acid. Complete it by inserting suitable words:

\[\ce{Active metal + Acid ->  \underline{\phantom{.......}} + \underline{\phantom{.......}}}\]


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