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Calculate the Total Torque Acting on the Body Shown in the Following Figure About the Point O.

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प्रश्न

Calculate the total torque acting on the body shown in the following figure about the point O.

बेरीज
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उत्तर

Torque about a point = Total force × Perpendicular distance

Let the anticlockwise torque and clockwise acting torque be positive and negative, respectively.

Torque at O due to 5 N force is zero as it is passing through O.

Torque at O due to 15 N force,

\[\tau_1  = 15 \times 6 \times  {10}^{- 2}  \times \sin37^\circ\] 

\[       = 15 \times 6 \times  {10}^{- 2}  \times \frac{3}{5}\] 

\[       = 0 . 54  N - m  .........\left(\text{anticlockwise} \right)\]

Torque at O due to 10 N force,

\[\tau_2  = 10 \times 4 \times  {10}^{- 2}  = 0 . 4  N - m  ........\left(\text{clockwise} \right)\]

Torque at O due to 20 N force,

\[\tau_3  = 20 \times 4 \times  {10}^{- 2}  \times \sin30^\circ\] 

\[ = 20 \times 4 \times  {10}^{- 2}  \times \frac{1}{2}\] 

\[ = 0 . 4  N - m  .........\left(\text{Anticlockwise} \right)\]

Resultant torque acting at O,

\[\tau = \left( 0 . 54 - 0 . 4 + 0 . 4 \right)\] 

\[     = 0 . 54  N - m  \left(\text{Anticlockwise} \right)\]

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पाठ 10: Rotational Mechanics - Exercise [पृष्ठ १९६]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 10 Rotational Mechanics
Exercise | Q 20 | पृष्ठ १९६

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