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Calculate the standard emf of the cell: Cd|CdX2+||CuX2+|Cu and determine the cell reaction. The standard reduction potentials of Cu2+|Cu and Cd2+|Cd are 0.34 V and −0.40 volts respectively. - Chemistry

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प्रश्न

Calculate the standard emf of the cell: \[\ce{Cd|Cd^{2+}||Cu^{2+}|Cu}\] and determine the cell reaction. The standard reduction potentials of Cu2+|Cu and Cd2+|Cd are 0.34 V and −0.40 volts respectively. Predict the feasibility of the cell reaction.

संख्यात्मक
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उत्तर

Cell reactions:

Oxidation at anode:

\[\ce{Cd_{(s)} -> Cd^{2+}_{( aq)} + 2e^-}\] \[\ce{(E^0_{ox})_{{Cd|Cd^{2+}}}}\] = 0.4 V

Reduction at cathode:

\[\ce{Cu^{2+}_{( aq)} + 2e^- -> Cu_{(s)}}\] \[\ce{(E^0_{red})_{{Cu^{2+}|Cu}}}\] = 0.34 V

\[\ce{Cd_{(s)} + 2e^- -> Cd^{2+}_{( aq)} + Cu_{(s)}}\]

`"E"_"cell"^0 = ("E"_"ox"^0)_"anode" + ("E"_"red"^0)_"cathode"`

= 0.4 + 0.34

= 0.74 V

emf is +ve, so ΔG is (−)ve, the reaction is feasible.

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Thermodynamics of Cell Reactions
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पाठ 9: Electro Chemistry - Evaluation [पृष्ठ ६६]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
पाठ 9 Electro Chemistry
Evaluation | Q 18. | पृष्ठ ६६

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