मराठी

Calculate the Percentage of Platinum in Ammonium Chloroplatinate (Nh4)2ptcl6.

Advertisements
Advertisements

प्रश्न

Calculate the percentage of platinum in ammonium chloroplatinate (NH4)2PtCl6.
[N = 14, H = 1, Pt = 195, Cl =35.5]
(Give your answer correct to the nearest whole number)

बेरीज
Advertisements

उत्तर

Molecular formula of ammonium chloroplatinate (NH4)2PtCl6 :
2 x (atomic mass of N + 8 x atomic mass of H) + atomic mass of platinum + 6 x atomic mass of chlorine
2 x (14 + 8 ) + 195 + 6 x 35.3= 444
444 parts of ammonium chloroplatinate contains 195 parts by weight of platinum
So, 100 parts will contain = 195 x 100/444 = 43.9‰ = 44‰

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Mole Concept and Stoichiometry - Questions from ICSE Examinations [पृष्ठ ११५]

APPEARS IN

फ्रँक Chemistry Part 2 [English] Class 10 ICSE
पाठ 5 Mole Concept and Stoichiometry
Questions from ICSE Examinations | Q 2002. 2. | पृष्ठ ११५

संबंधित प्रश्‍न

Calculate the percentage composition of oxygen in lead nitrate [Pb(NO3)2]. [Pb = 207, N= 14, O = 16]


Potassium nitrate on strong heating decomposes as under :
2KNO3 → 2KNO2 + O2
Calculate : Weight of oxygen formed when 5.05g of potassium nitrate decomposes completely.
(K = 39, 0 = 16, N = 14)


What is the mass of nitrogen in 1000Kg of urea [CO(NH2)2] ?
[H = 1, C= 12, N= 14, O = 16]


When excess lead nitrate solution was added to a solution of sodium sulphate, 15.1g of lead sulphate was precipitated. What mass of sodium sulphate was present in the original solution?
Na2SO4 + Pb(NO3)2 → PbSO4 + 2NaNO3
(H = 1, C = 12, O = 16, Na = 23, S = 32, Pb = 207)


Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C3H5).
(Atomic mass: C = 14, O = 16, H = 1, Molar Volume = 22.4 dm3 at STP.)


Calculate the relative molecular mass of:

Potassium chlorate


Which of the following contains maximum number of molecules?


Calculate the mass of nitrogen supplied to soil by 5 kg of urea [CO(NH2)2].

[O = 16; N = 14; C = 12; H = 1]


The following question refers to one mole of chlorine gas.

If the relative atomic mass of chlorine is 35.5, what will be the mass of 1 mole of chlorine gas?


67.2 litres of hydrogen combines with 44.8 litres of nitrogen to form ammonia under specific conditions as:

\[\ce{N2_{(g)} + 3H2_{(g)} -> 2NH3_{(g)}}\]

Calculate the volume of ammonia produced. What is the other substance, if any, that remains in the resultant mixture?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×