Advertisements
Advertisements
प्रश्न
Calculate consumer’s surplus if the demand function p = 122 – 5x – 2x2, and x = 6
Advertisements
उत्तर
Demand function p = 122 – 5x – 2x2 and x = 6
When x = 6
p = 122 – 5(6) – 2(6)2
= 122 – 30 – 2(36)
= 122 – 102
= 20
∴ p0 = 20
.S = `int_^x` (demand function) dx – (Price × quantity demanded)
- `int_0^6` (122 – 5x – 2x2) dx – (20 × 6)
= `[122x - 5(x^2/2) - 2(x^3/3)]_0^6 - 120`
= `[122(6) - ((6)^2/2) - 2((6)^3/3) - [0]] - 120`
= `[732 - ((5(36))/2) - ((2(216))/3)] - 120`
= [732 – 5(18) – 2(72)] – 120
= 732 – 90 – 144 – 120
= 732 – 354
= 378
∴ CS = 378 units
APPEARS IN
संबंधित प्रश्न
If the marginal revenue function for a commodity is MR = 9 – 4x2. Find the demand function.
The marginal cost of production of a firm is given by C'(x) = 5 + 0.13x, the marginal revenue is given by R'(x) = 18 and the fixed cost is ₹ 120. Find the profit function
The marginal cost function of a commodity is given by MC = `14000/sqrt(7x + 4)` and the fixed cost is ₹ 18,000. Find the total cost and average cost
If the marginal cost (MC) of production of the company is directly proportional to the number of units (x) produced, then find the total cost function, when the fixed cost is ₹ 5,000 and the cost of producing 50 units is ₹ 5,625
The demand function for a commodity is p =`36/(x + 4)`. Find the consumer’s surplus when the prevailing market price is ₹ 6
The demand and supply functions under perfect competition are pd = 1600 – x2 and ps = 2x2 + 400 respectively. Find the producer’s surplus
Choose the correct alternative:
If the marginal revenue function of a firm is MR = `"e"^((-x)/10)`, then revenue is
Choose the correct alternative:
If MR and MC denotes the marginal revenue and marginal cost functions, then the profit functions is
Choose the correct alternative:
If MR and MC denote the marginal revenue and marginal cost and MR – MC = 36x – 3x2 – 81, then the maximum profit at x is equal to
A company requires f(x) number of hours to produce 500 units. It is represented by f(x) = 1800x–0.4. Find out the number of hours required to produce additional 400 units. [(900)0.6 = 59.22, (500)0.6 = 41.63]
