Question

Balance the following equation by the ion electron method.

\[\ce{KMnO4 + SnCl2 + HCl -> MnCl2 + SnCl4 + H2O + KCl}\]

Answer 1

\[\ce{M^{+7}nO^-_4 -> Mn^2+}\] ........(1)

and \[\ce{Sn^2+ -> Sn^4+}\] ........(2)

\[\ce{MnO^-_4 + 8H^+ + 5e^- -> Mn^2+ + 4H2O}\] ....[Eq. (1)]

\[\ce{Sn^2+ -> Sn^4+ + 2e^-}\] .........[Eq. (2)]

\[\ce{2MnO^-_4 + 16H^+ + 10e^- -> 2Mn^2+ + 8H2O}\] .......[(1) × 2]

\[\ce{5Sn^2+ -> 5Sn^4+ + 10e^-}\] ......[(2) × 5]

\[\ce{2MnO^-_4 + 5Sn^2+ + 16^H+ -> 2Mn^2+ + 5Sn^4+ + 8H2O}\]