मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Assuming the Earth to Be a Sphere of Uniform Mass Density, How Much Would a Body Weigh Half Way Down to the Centre of the Earth If It Weighed 250 N on the Surface - Physics

Advertisements
Advertisements

प्रश्न

Assuming the earth to be a sphere of uniform mass density, how much would a body weigh half way down to the centre of the earth if it weighed 250 N on the surface?

Advertisements

उत्तर १

Weight of a body of mass m at the Earth’s surface, W = mg = 250 N

Body of mass m is located at depth,  d = `1/2R_e`

Where

`R_e` = Radius of Earth

Acceleration due to gravity at depth (d) is given by the relation:

`g = (1-d/R_e)g`

`=(1-(R_e)/(2xxR_e))g = 1/2 g`

Weight of the body at depth d,

W' = mg

`= mxx1/2g = 1/2 mg = 1/2 W`

`=1/2 xx 250 = 125 N`

shaalaa.com

उत्तर २

As`g_d = g(1-d/R) => mg_d  = mg(1-d/R)`

Here `d= R/2`

`:. mg_d = (250)xx (1-"R/2"/R) = 250 xx 1/2 = 125 N`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

Is there any meaning of "Weight of the earth"?


An apple falls from a tree. An insect in the apple finds that the earth is falling towards it with an acceleration g. Who exerts the force needed to accelerate the earth with this acceleration g?


The acceleration of moon with respect to earth is 0⋅0027 m s−2 and the acceleration of an apple falling on earth' surface is about 10 m s−2. Assume that the radius of the moon is one fourth of the earth's radius. If the moon is stopped for an instant and then released, it will fall towards the earth. The initial acceleration of the moon towards the earth will be


The acceleration of the moon just before it strikes the earth in the previous question is


Suppose, the acceleration due to gravity at the earth's surface is 10 m s−2 and at the surface of Mars it is 4⋅0 m s−2. A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?


If the acceleration due to gravity at the surface of the earth is g, the work done in slowly lifting a body of mass m from the earth's surface to a height R equal to the radius of the earth is


What is the acceleration due to gravity on the top of Mount Everest? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is 9.80 m s−2.


A particle is fired vertically upward from earth's surface and it goes up to a maximum height of 6400 km. Find the initial speed of particle.


A particle is fired vertically upward with a speed of 15 km s−1. With what speed will it move in interstellar space. Assume only earth's gravitational field.


If the acceleration due to gravity becomes 4 times its original value, then escape speed ____________.


Explain the variation of g with latitude.


Explain the variation of g with altitude.


Calculate the change in g value in your district of Tamil nadu. (Hint: Get the latitude of your district of Tamil nadu from Google). What is the difference in g values at Chennai and Kanyakumari?


If both the mass and the radius of the earth decrease by 1%, then the value of acceleration due to gravity will


A person whose mass is 100 kg travels from Earth to Mars in a spaceship. Neglect all other objects in the sky and take acceleration due to gravity on the surface of the Earth and Mars as 10 m/s2 and 4 m/s2 respectively. Identify from the below figures, the curve that fits best for the weight of the passenger as a function of time.


If R is the radius of the earth and g is the acceleration due to gravity on the earth's surface, the mean density of the earth is ______.


A ball is immersed in water kept in container and released. At the same time container is accelerated in horizontal direction with acceleration, `sqrt44` m/s2. Acceleration of ball w.r.t. container is ______ m/s2 (specific gravity of ball = 12/17, g = 10 m/s2)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×