Advertisements
Advertisements
प्रश्न
Arun bought a car for ₹ 3,50,000. The next year, the price went upto ₹ 3,70,000. What was the percentage of price increase?
Advertisements
उत्तर
Initial price = ₹ 350000
Final price = ₹ 370000
Increase = ₹ 20000
Increase% = `20000/350000xx 100`
= `5 5/7%`
APPEARS IN
संबंधित प्रश्न
On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the per cent decrease in the people visiting the zoo on Monday?
The population of a city decreased from 25,000 to 24,500. Find the percentage decrease.
A school team won 6 games this year against 4 games won last year. What is the percent increase
Kayal scored 225 marks out of 500 in revision test 1 and 265 out of 500 marks in revision test 2. Find the percentage of increase in her score
Increase of a number from 150 to 162 is equal to increase of ______ per cent.
Three times a number is 200% increase in the number, then one-third of the same number is 200% decrease in the number.
Number of students appearing for class X CBSE examination increases from 91,422 in 1999 – 2000 to 11,6054 in 2008 – 09. Increase in the number of students appeared is approximately 27%.
For an amount, explain why, a 20% increase followed by a 20% decrease is less than the original amount.
Sunscreens block harmful ultraviolet (UV) rays produced by the sun. Each sunscreen has a Sun Protection Factor (SPF) that tells you how many minutes you can stay in the sun before you receive one minute of burning UV rays. For example, if you apply sunscreen with SPF 15, you get 1 minute of UV rays for every 15 minutes you stay in the sun.
Suppose a sunscreen allows 25% of the sun’s UV rays.
- What fraction of UV rays does this sunscreen block? Give your answer in lowest terms.
- Use your answer from Part (a) to calculate this sunscreen’s SPF. Explain how you found your answer.
If A is increased by 20%, it equals B. If B is decreased by 50%, it equals C. Then ______ % of A is equal to C.
