Advertisements
Advertisements
प्रश्न
Arun bought a car for ₹ 3,50,000. The next year, the price went upto ₹ 3,70,000. What was the percentage of price increase?
Advertisements
उत्तर
Initial price = ₹ 350000
Final price = ₹ 370000
Increase = ₹ 20000
Increase% = `20000/350000xx 100`
= `5 5/7%`
APPEARS IN
संबंधित प्रश्न
A school team won 6 games this year against 4 games won last year. What is the percent increase
In the year 2015 ticket to the world cup cricket match was ₹ 1,500. This year the price has been increased by 18%. What is the price of a ticket this year?
Radhika bought a car for Rs 2,50,000. Next year its price decreased by 10% and further next year it decreased by 12%. In the two years overall decrease per cent in the price of the car is ______.
Increase of a number from 150 to 162 is equal to increase of ______ per cent.
2500 is greater than 500 by ______ %.
Three times a number is 200% increase in the number, then one-third of the same number is 200% decrease in the number.
In 1975, the consumption of water for human use was about 3850 cu.km/year. It increased to about 6000 cu.km/year in the year 2000. Find the per cent increase in the consumption of water from 1975 to 2000. Also, find the annual per cent increase in consumption (assuming water consumption increases uniformly).
Sunscreens block harmful ultraviolet (UV) rays produced by the sun. Each sunscreen has a Sun Protection Factor (SPF) that tells you how many minutes you can stay in the sun before you receive one minute of burning UV rays. For example, if you apply sunscreen with SPF 15, you get 1 minute of UV rays for every 15 minutes you stay in the sun.
Suppose a sunscreen allows 25% of the sun’s UV rays.
- What fraction of UV rays does this sunscreen block? Give your answer in lowest terms.
- Use your answer from Part (a) to calculate this sunscreen’s SPF. Explain how you found your answer.
45% of the population of a town are men and 40% are women. What is the percentage of children?
