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प्रश्न
Arrange the following.
In increasing order of boiling point C6H5OH, (CH3)2NH, C2H5NH2.
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उत्तर
Since the electronegativity of O is higher than that of N, therefore, alcohols form stronger H-O bonds than amines. In other words, the boiling points of alcohols are higher than those of amines of comparable molecular masses. Therefore the boiling point of C6H5OH (46) is higher than those of (CH3)2NH (45) and C2H5NH2 (45).
Further, the extent of H-bonding depends upon the number of H-atoms on the N-atom. Therefore 1° amine with two H-atoms on the N-atom has higher boiling points than 2° amines having only one H-atom. Therefore the boiling point of C2H5NH2 is higher than that of(CH3)2NH.
The increasing order of boiling point is, (CH3)2NH < C2H5NH2 < C6H5OH.
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संबंधित प्रश्न
Choose the most correct option.
The hybridisation of nitrogen in primary amine is ____________.
Choose the most correct option.
Carbylamine test is given by ____________.
How are amines classified depending on the functional group? Give one example of each class of amines.
The order of basic strength for methyl substituted amines in aqueous solution is ____________.
IUPAC name for the amine is:
\[\begin{array}{cc}
\phantom{.}\ce{CH3}\\
|\phantom{..}\\
\ce{CH3 - N - C - CH2 - CH3}\\
\phantom{.}|\phantom{.....}|\phantom{........}\\
\phantom{}\ce{CH3}\phantom{..}\ce{C2H5}\phantom{....}
\end{array}\]
Write a short note on the following.
Mustard oil reaction
The main product is formed by treating an alkyl or benzyl halide with excess ammonia ____________.
The amine formed from an amide by mean of bromine and alkali has how many number of carbon atoms?
Assertion A: Aniline on nitration yields ortho, meta and para nitro derivatives of aniline.
Reason R: Nitrating mixture is a storng acidic mixture.
In the light of the above statements, choose the correct answer from the options given below:
Write short notes on the following
Ammonolysis
