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प्रश्न
Arrange the following.
In increasing order of boiling point C6H5OH, (CH3)2NH, C2H5NH2.
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उत्तर
Since the electronegativity of O is higher than that of N, therefore, alcohols form stronger H-O bonds than amines. In other words, the boiling points of alcohols are higher than those of amines of comparable molecular masses. Therefore the boiling point of C6H5OH (46) is higher than those of (CH3)2NH (45) and C2H5NH2 (45).
Further, the extent of H-bonding depends upon the number of H-atoms on the N-atom. Therefore 1° amine with two H-atoms on the N-atom has higher boiling points than 2° amines having only one H-atom. Therefore the boiling point of C2H5NH2 is higher than that of(CH3)2NH.
The increasing order of boiling point is, (CH3)2NH < C2H5NH2 < C6H5OH.
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संबंधित प्रश्न
In the following
The compound ‘B’ is _______.
(A) Propan–1–amine
(B) Propan–2–amine
(C) Isopropylamine
(D) Dimethylamine
Write a short note on the following.
Ammonolysis
Write a short note on the following.
Mustard oil reaction
How will you distinguish between primary secondary and tertiary aliphatic amines?
Arrange the following.
Increasing order of basic strength C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2.
(C2H5)2CHNH2. The following amine can be classified as:
The reaction of NHO2 with 'A' gives quartering ammonium salt. A is which of the following?
\[\begin{array}{cc}
\ce{O}\phantom{.........}\\
||\phantom{.........}\\
\ce{H - \underset{(A)}{C} - NH - CH3}
\end{array}\]
and
\[\begin{array}{cc}
\ce{O}\\
||\\
\ce{CH3 - \underset{(B)}{C} - NH2}
\end{array}\]
are which type of isomers?
Write short note on the following.
Ammonolysis
Write short note on Ammonolysis.
