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प्रश्न
Arrange the following.
In increasing order of boiling point C6H5OH, (CH3)2NH, C2H5NH2.
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उत्तर
Since the electronegativity of O is higher than that of N, therefore, alcohols form stronger H-O bonds than amines. In other words, the boiling points of alcohols are higher than those of amines of comparable molecular masses. Therefore the boiling point of C6H5OH (46) is higher than those of (CH3)2NH (45) and C2H5NH2 (45).
Further, the extent of H-bonding depends upon the number of H-atoms on the N-atom. Therefore 1° amine with two H-atoms on the N-atom has higher boiling points than 2° amines having only one H-atom. Therefore the boiling point of C2H5NH2 is higher than that of(CH3)2NH.
The increasing order of boiling point is, (CH3)2NH < C2H5NH2 < C6H5OH.
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संबंधित प्रश्न
In the following
The compound ‘B’ is _______.
(A) Propan–1–amine
(B) Propan–2–amine
(C) Isopropylamine
(D) Dimethylamine
Choose the most correct option.
The hybridisation of nitrogen in primary amine is ____________.
Assertion: Acetamide on reaction with KOH and bromine gives acetic acid.
Reason: Bromine catalyses hydrolysis of acetamide.
Arrange the following:
In increasing order of solubility in water:
C6H5NH2, (C2H5)2NH, C2H5NH2
Arrange the following.
Increasing order of basic strength C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2.
Arrange the following.
In decreasing order of basic strength
How will you convert diethylamine into N-nitrosodiethylamine?
The following amine can be classified as:
Arrange the following in the increasing order of their basic strength:
C2H5NH2, C6H5NH2, (C2H5)2NH
\[\begin{array}{cc}
\ce{O}\phantom{.........}\\
||\phantom{.........}\\
\ce{H - \underset{(A)}{C} - NH - CH3}
\end{array}\]
and
\[\begin{array}{cc}
\ce{O}\\
||\\
\ce{CH3 - \underset{(B)}{C} - NH2}
\end{array}\]
are which type of isomers?
