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प्रश्न
Arrange the following.
In increasing order of boiling point C6H5OH, (CH3)2NH, C2H5NH2.
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उत्तर
Since the electronegativity of O is higher than that of N, therefore, alcohols form stronger H-O bonds than amines. In other words, the boiling points of alcohols are higher than those of amines of comparable molecular masses. Therefore the boiling point of C6H5OH (46) is higher than those of (CH3)2NH (45) and C2H5NH2 (45).
Further, the extent of H-bonding depends upon the number of H-atoms on the N-atom. Therefore 1° amine with two H-atoms on the N-atom has higher boiling points than 2° amines having only one H-atom. Therefore the boiling point of C2H5NH2 is higher than that of(CH3)2NH.
The increasing order of boiling point is, (CH3)2NH < C2H5NH2 < C6H5OH.
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संबंधित प्रश्न
In the following
The compound ‘B’ is _______.
(A) Propan–1–amine
(B) Propan–2–amine
(C) Isopropylamine
(D) Dimethylamine
Choose the most correct option.
Which type of amine does produce N2 when treated with HNO2?
Choose the most correct option.
Identify ‘B’ in the following reactions
\[\ce{CH3 - C ≡ N ->[Na/C2H5OH] A ->[NaNO2/dilHCl]B}\]
Which one of the following is most basic?
How will you distinguish between primary secondary and tertiary aliphatic amines?
Arrange the following.
In decreasing order of basic strength in gas phase (C2H5)NH2, (C2H5)NH, (C2H5)3N and NH3.
The following amine can be classified as (C2H5)2NH:
The reaction of NHO2 with 'A' gives quartering ammonium salt. A is which of the following?
Assertion A: Aniline on nitration yields ortho, meta and para nitro derivatives of aniline.
Reason R: Nitrating mixture is a storng acidic mixture.
In the light of the above statements, choose the correct answer from the options given below:
Write a short note on the following.
Ammonolysis
