मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Area of the region bounded by y = x4, x = 1, x = 5 and the X-axis is _______. - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Area of the region bounded by y = x4, x = 1, x = 5 and the X-axis is _______.

रिकाम्या जागा भरा
Advertisements

उत्तर

Area of the region bounded by y = x4, x = 1, x = 5 and the X-axis is `bbunderline((3124)/(5)  sq. units)`.

Explanation:

Let A be the required area.

Consider the equation y = x4.

∴ A = `int_1^5 y*dx`

= `int_1^5 x^4*dx`

= `[(x^5)/5]_1^5`

= `(1)/(5)[x^5]_1^5`

= `(1)/(5)[(5)^5 - (1)^5]`

= `(1)/(5)(3125 - 1)`

∴ A = `(3124)/(5)` sq . units.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Applications of Definite Integration - Miscellaneous Exercise 7 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 7 Applications of Definite Integration
Miscellaneous Exercise 7 | Q 2.1 | पृष्ठ १५८

संबंधित प्रश्‍न

Find the area of the region in the first quadrant enclosed by the x-axis, the line y = x and the circle x2 + y2 = 32.


Find the area of the region bounded by the curve y2 = x and the lines x = 1, x = 4 and the x-axis.


Find the area of the region bounded by y2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.


Find the area of the region bounded by the parabola y = x2 and y = |x| .


Find the area of the region bounded by the curve y2 = 4x and the line x = 3


Area lying in the first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2 is ______.


Find the area between the curves y = x and y = x2


Find the area of the region {(x, y) : y2 ≤ 4x, 4x2 + 4y2 ≤ 9}


Find the area enclosed between the parabola 4y = 3x2 and the straight line 3x - 2y + 12 = 0.


Find the area of the smaller region bounded by the ellipse \[\frac{x^2}{9} + \frac{y^2}{4} = 1\] and the line \[\frac{x}{3} + \frac{y}{2} = 1 .\]


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


Find the area of the region bounded by the following curves, the X-axis, and the given lines:

y = `sqrt(6x + 4), x = 0, x = 2`


Find the area of the region bounded by the following curves, the X-axis and the given lines:  2y = 5x + 7, x = 2, x = 8


Area of the region bounded by x2 = 16y, y = 1 and y = 4 and the Y-axis, lying in the first quadrant is _______.


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


State whether the following is True or False :

The area of the portion lying above the X-axis is positive.


Choose the correct alternative:

Area of the region bounded by y2 = 16x, x = 1 and x = 4 and the X axis, lying in the first quadrant is ______


Choose the correct alternative:

Area of the region bounded by x = y4, y = 1 and y = 5 and the Y-axis lying in the first quadrant is ______


The area of the region bounded by the curve y2 = x and the Y axis in the first quadrant and lines y = 3 and y = 9 is ______


Find area of the region bounded by the curve y = – 4x, the X-axis and the lines x = – 1 and x = 2


Find area of the region bounded by the parabola x2 = 4y, the Y-axis lying in the first quadrant and the lines y = 3


Find the area of the region bounded by the curve x = `sqrt(25 - y^2)`, the Y-axis lying in the first quadrant and the lines y = 0 and y = 5


Area enclosed between the curve y2(4 - x) = x3 and line x = 4 above X-axis is ______.


The area of the region bounded by the curve y = x IxI, X-axis and the ordinates x = 2, x = –2 is ______.


The area of the circle `x^2 + y^2 = 16`, exterior to the parabola `y = 6x`


The area bounded by the x-axis and the curve y = 4x – x2 – 3 is ______.


Area bounded by y = sec2x, x = `π/6`, x = `π/3` and x-axis is ______.


The area bounded by the curve | x | + y = 1 and X-axis is ______.


The area bounded by the curve, y = –x, X-axis, x = 1 and x = 4 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×