Advertisements
Advertisements
प्रश्न
Area of a triangle PQR right-angled at Q is 60 cm2 (see figure). If the smallest side is 8 cm long, find the length of the other two sides.

Advertisements
उत्तर
Given, area of ΔPQR = 60 cm2 and side PQ = 8 cm
∴ Area of ΔPQR = `1/2` × PQ × QR ...[∵ Area of triangle = Base × Height]
⇒ 60 = `1/2` × 8 × QR
⇒ QR = `(60 xx 2)/8`
⇒ QR = 15 cm
In right-angled ΔPQR,
PR2 + PQ2 + QR2 ...[By Pythagoras theorem]
⇒ PR2 + 82 + 152 = 64 + 225
⇒ PR2 = 289
⇒ PR = `sqrt(289)` = 17 cm
Hence, the length of two sides are 15 cm and 17 cm.
APPEARS IN
संबंधित प्रश्न
Find the relation between x and y if, the points A(x, y), B(-5, 7) and C(-4, 5) are collinear.
Find the values of k for which the points A(k + 1, 2k), B(3k, 2k + 3) and (5k – 1, 5k) are collinear.
Find values of k if area of triangle is 4 sq. units and vertices are (−2, 0), (0, 4), (0, k).
For what value of a point (a, 1), (1, -1) and (11, 4) are collinear?
Show that the points A (3,1) , B (0,-2) , C(1,1) and D (4,4) are the vertices of parallelogram ABCD.
Find the value of k so that the area of the triangle with vertices A (k+1, 1), B(4, -3) and C(7, -k) is 6 square units
Find a relation between x and y, if the points A(x, y), B(-5, 7) and C(-4, 5) are collinear.
Points A(3, 1), B(12, –2) and C(0, 2) cannot be the vertices of a triangle.
The dimensions of a rectangle ABCD are 51 cm × 25 cm. A trapezium PQCD with its parallel sides QC and PD in the ratio 9 : 8, is cut off from the rectangle as shown in the following figure. If the area of the trapezium PQCD is `5/6` th part of the area of the rectangle, find the lengths QC and PD.

Area of triangle MNO in the following figure is ______.

