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प्रश्न
Answer the following question.
Explain briefly how Rutherford scattering of α-particle by a target nucleus can provide information on the size of the nucleus.
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उत्तर
- Most of the space inside the atom is empty became most of the α-particle passed through the gold foil without getting deflected.
- Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.
- A very small fraction of α-particle were deflected by very large angles, indicating that all the +ve charge and mass of the gold atom were concentrated in a very small volume within the atom.
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संबंधित प्रश्न
Suppose you are given a chance to repeat the alpha-particle scattering experiment using a thin sheet of solid hydrogen in place of the gold foil. (Hydrogen is a solid at temperatures below 14 K.) What results do you expect?
An electron in an atom revolves round the nucleus in an orbit of radius r with frequency v. Write the expression for the magnetic moment of the electron.
In Geiger-Marsden experiment prediction was that ______.
The basic force acting on the alpha particles using Coulomb's law is ______.
The first line of Balmer series (Hα) in the spectrum of hydrogen is obtained when an electron of hydrogen atom goes from ______.
For 7.7 Mev alpha particles scattering from aluminium (Z = 13), the distance of closest approach in a bead on collision is ______.
Useful data
`1/(4 pi ∈_0) = 8.99 xx 10^9` newton m2C-2; c = 1.60 × 10-19 C; leV = 1.60 × 10-19j.
Which of the following transition in a hydrogen atom emit photon of the highest frequency:
O2 molecule consists of two oxygen atoms. In the molecule, nuclear force between the nuclei of the two atoms ______.
An alpha nucleus of energy `1/2`mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to ______.
- v2
- `1/"m"`
- `1/"v"^2`
- `1/"Ze"`
Differentiate between the 'distance of the closest approach' and the 'impact parameter.'
