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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Answer the following : Find the centre and radius of the circle x = 3 – 4 sinθ, y = 2 – 4cosθ

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प्रश्न

Answer the following :

Find the centre and radius of the circle x = 3 – 4 sinθ, y = 2 – 4cosθ

बेरीज
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उत्तर

Given, x = 3 – 4 sinθ, y = 2 – 4cosθ

∴ x – 3 –4 sinθ, y –2 =  – 4cosθ

On squaring and adding, we get

(x – 3)2 + (y – 2)2 = (–4 sinθ)2 + (–4 cosθ)2

∴ (x – 3)2 + (y – 2)2 = 16sin2θ + 16cos2θ

∴ (x – 3)2 + (y – 2)2 = 16(sin2θ + cos2θ)

∴ (x – 3)2 + (y – 2)2 = 16(1)

∴ (x – 3)2 + (y – 2)2 = 16

∴ (x – 3)2 + (y – 2)2 = 42

Comparing this equation with

(x – h)2 + (y – k)2 = r2, we get

h = 3, k = 2, r = 4

∴ Centre of the circle is (3, 2) and radius is 4.

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पाठ 6: Circle - Miscellaneous Exercise 6 [पृष्ठ १३७]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
पाठ 6 Circle
Miscellaneous Exercise 6 | Q II. (2) | पृष्ठ १३७

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