मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Answer in brief. With the help of the crystal field, the energy-level diagram explains why the complex [Cr(en)3]3⊕ is coloured.

Advertisements
Advertisements

प्रश्न

Answer in brief.

With the help of the crystal field, the energy-level diagram explains why the complex [Cr(en)3]3⊕ is coloured.

टीपा लिहा
Advertisements

उत्तर

CFT:

ligands are treated as point charges interaction, but ligands & metal are purely electrostatic.

Metal has dorbital = dxy, dxz, dyz, dx2, dy2, dz2

When ligands approach metal, the degeneracy of metal is disturbed.

spit int 2 energy levels = t2g & eg
dxy, dxz, dxz

[Cr(en)3]+3 = en = ethylene diamine bidentate ligand

n = 3

`sqrt(n(n+2)) = sqrt(3(3+2))`

`sqrt15`

= 3.83 B.M

Paramagnetic :

d - d transition = [Cr(en)3]+3 = coloured property

shaalaa.com
Theories of Bonding in Complexes
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Coordination Compounds - Exercises [पृष्ठ २०८]

APPEARS IN

बालभारती Chemistry [English] Standard 12 Maharashtra State Board
पाठ 9 Coordination Compounds
Exercises | Q 3.10 | पृष्ठ २०८

संबंधित प्रश्‍न

On the basis of CFT predict the number of unpaired electrons in [CrF6]3-.


What are the high-spin complexes?


Answer in brief.

[CoCl4]2− is a tetrahedral complex. Draw its box orbital diagram. State which orbitals participate in hybridization.


Answer in brief.

[CoCl4]2- is a tetrahedral complex. Draw its box orbital diagram. State which orbitals participate in hybridization.


Answer the following question.

Draw a qualitatively energy-level diagram showing d-orbital splitting in the octahedral environment. Predict the number of unpaired electrons in the complex [Fe(CN)6]4-. Is the complex diamagnetic or paramagnetic? Is it coloured? Explain.


Explain, why [Co(NH3)6]3+ ion is low spin? Calculate number of unpaired electrons and write the geometry of [Co(NH3)6]3+.


Answer the following with respect to [CoF6]3– ion

  1. Type of hybridization
  2. Number of unpaired electrons
  3. Geometry of complex ion
  4. Magnetic property

Chlorophyll and haemoglobin are complexes of ____________ respectively.


The number of unpaired electrons in the complex ion [CoF6]3− is ____________.


The INCORRECT match for complex with its geometry is:


The number of unpaired electrons in the complex ion [NiCl4]2− is ____________.


Identify the CORRECT statements regarding [Co(NH3)6]3+.

I. Oxidation state of metal ion = +3

II. It is a high spin complex.

III. It is paramagnetic.

IV. Metal ion undergoes d2sp3 hybridization.


What is the value of primary valence of Co in CoCl3?


What is the type of magnetic behavior and geometry respectively in Cuproammonium sulphate (Atomic number of Cu = 29)?


Which of the following types of square planar complexes can show geometrical isomerism [M = metal, a, b, = monodentate ligand]?


Describe the bonding in the tetrahedral complex Ni(CO)4 on the basis of valence bond theory. Give the orbital diagrams of metal atoms in free state and in the complex. Mention the number of unpaired electrons in the complex.


Give VBT description of the bonding in a square planar complex [Cu(NH3) 4]2+. Show orbital diagrams for free metal ion and metal ion in the complex. Which hybrid orbitals are used by metal for bonding? State magnetic nature of the complex.


Give a valence bond description of the bonding in the high spin complex [MnCl6]3− Include orbital diagram for the free metal ion and the metal ion in the complex. Indicate which hybrid orbitals the metal ion uses for bonding. Specify the number of unpaired electrons.


Give the limitations of VBT.


A compound forms hexagonal close packed (hcp) structure. What is the number of (i) Octahedral voids, (ii) Tetrahedral voids, (iii) Total voids formed in 0.7 mol of it.


Mention the type of hybridization in [Co(NH3)6]3+ complex.


Mention the number of unpaired electrons and geometry of the following complex:

\[\ce{[Ni(CN)4]^2-}\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×